[SOLVED] How check that second level menu is displayed?

[bunak]

Hi all,
I am newbie in CMSMS and I need Your help.
I have very simple template, part of it is here:

Code: Select all

		<div class="menuhorni">
         <h2 class="accessibility">Navigace</h2>
         {menu template='simple_navigation.tpl' number_of_levels="1" collapse='1'}
		</div>
		<!-- /menu horni -->
	</div>
	<div class="drobek">
		Jste zde: {breadcrumbs starttext='' root='dom?' delimiter='»'}
		 <hr class="accessibility" />
	</div>
	<div class="levy">

         <h2>{title}</h2>
         {content} <br />
	
	</div>
	<div class="pravy">
--------------------------------------------------------------------------------------------------------------------------------
if{menu below is displayed}
   <h2>Menu header</h2>
{/if}
--------------------------------------------------------------------------------------------------------------------------------      
	 {menu template='simple_navigation.tpl' start_level="2" collapse='1'}

         <h2>Novinky</h2>
           <div class="sedivy">
             {news number='2' detailpage='news' category='General'}
           </div>

and I need help with conditionally displayed part of page. ( part between -------)
Is there in CMSMS menu module any variable, which say, that menu below this part was displayed? I need display Menu header only if  menu below is displayed.

look at: http://www.pkcomp.cz/cz/index.php/triline
on right column there is menu item "Ceník služeb Triline" which need header something like Menu.

Thanks for Your help


I have rewrite action.default in Menu module. Added new variable which show actual menu level

[hexdj]

I am not 100% sure what you're trying to accomplish.
Did you try editing the MENU TEMPLATE, you find it by going to Layout > Menu Manager and find your template in there, and you can edit it. To find out what Variables are available in your template add the following to your MENU Template

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{get_template_vars}