[Solved] Displaying the child objects of a drop down menu

[DoctorWho]

I don't know if this is the right section for this post, feel free to move it if need be.

Is it possible to display the child objects of a drop-down menu on a web page using the menu manager?

My site currently looks like this:

and I want it to look like this when the parent menu object has children:

[Dr.CSS]

Are you wanting the child pages of the active top menu item to be displayed on the left side?...

[DoctorWho]

You got it!

[DoctorWho]

This is what I have so far, but it's out putting the entire navigation. I just want it to out put the child objects for each section without the parent being displayed.

Code: Select all

{if $count > 0}
<ul style="margin-left: 15px; padding-left: 0;">
{foreach from=$nodelist item=node}
{if $node->depth > $node->prevdepth}
{repeat string="<ul> times=$node->depth-$node->prevdepth}
{elseif $node->depth < $node->prevdepth}
{repeat string="</li></ul>" times=$node->prevdepth-$node->depth}
</li>
{elseif $node->index > 0}</li>
{/if}

<li><p><a href="{$node->url}" {if $node->target}onclick="target='newwindow'" {/if}>{$node->menutext}</a></p>

{/foreach}
{repeat string="</li></ul>" times=$node->depth-1}</li>
</ul>
{/if}

[Dr.CSS]

First of all you really should be using style= in your code, use CSS, second you can get the child pages quite easily by using a default combo of menu calls like it explains here...

http://multiintech.com/defaultcontent/i ... e=top_left

[DoctorWho]

Thanks Dr.CSS! That's just what I was looking for!

[Dr.CSS]

That's why I always recommend reading all the default content as it has a lot of useful info...